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Solve equations for!!!!!!!!!!!!!!!!!!!!!!!!!!!!

+1 vote

 

{-3x+2y=16 5x-3y=-25}?

asked Mar 21, 2013 in ALGEBRA 2 by angel12 Scholar

1 Answer

+1 vote

-3x + 2y = 16    -(1)

5x - 3y  = -25    -(2)

Multiply each side by 3 in the first equation

3(-3x + 2y) = 3(16)

Recall : Distributive property a(b + c) = ab + ac

-9x +6y = 48    -(3)

Multiply each side by 2 in the second equation

2(5x - 3y)  = 2(-25)

Recall : Distributive property a(b + c) = ab + ac

10x -6y = -50    -(4)

Add Third and fourth equations then

-9x +10x + 6y - 6y  = 48 - 50

x + 0y = -2

x +0 = -2

x = -2

Substitute x = -2 in the first equation -3x + 2y  = 16 then

-3(-2) +2y = 16

6 + 2y = 16

Subtract  6 from each side

There fore 2y = 16 - 6

2y = 10

Divide each side by 2

y  = 10 / 2

y = 5

The solution of equation : (-2 , 5).

 

 

 

 

answered Mar 22, 2013 by diane Scholar

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