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Na2CO3 +2HCl ---> 2NaCL +H2O +CO2

1) What is the mass of sodium chloride formed?

During this experiment, the mass of the casserole and the sodium carbonate was 49.08 g. Aftera week, the mass of the casserole and sodium chloride was 49.80 g. So how do I find the mass formed.

2) What is the theoretical yoied of sodium chloride?

3) What is the percentage yield of sodium  chloride?
asked Nov 16, 2014 in CHEMISTRY by heather Apprentice

1 Answer

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(1)

Molar mass of  Na2CO3 is = 105.9885 g/mol .

Molar mass of  NaCL is = 58.44 g/mol .

Mass of   Na2CO3 is  49.08 g .

Molar weight of  Na2CO3 is  = ( mass of  Na2CO3 )/(molar mass of Na2CO3 )

                                            =  49.08 g / 58.44 g/mol  = 0.8398 mol .

The ratio of Na2CO3 and NaCL is 1/2            [From balancing equation ]

So the molar weight of NaCL is = 0.8398 mol * (1/2)

                                               = 0.4199 mol .

So the mass of the NaCL is = molar weight * molar mass 

                                         = 0.4199 mol  * 58.44 g/mol

                                        = 24.54 g .

Hence the mass of sodium chloride formed is 24.54 g .

answered Nov 21, 2014 by yamin_math Mentor

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