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Chemistry HElp? solubility help?

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a) Calculate the solubility of silver chloride in 10.0 M ammonia given the following informa$on:

Ksp (AgCl) = 1.6 × 10–10
Ag+ +NH3<-> AgNH3+ K=2.1×103

AgNH3+ + NH3 <->Ag(NH3)2+ K = 8.2 × 103

 

b)Calculate the concentra$on of NH3 in the final equilibrium

mixture.

 

 

asked Apr 30, 2015 in CHEMISTRY by heather Apprentice

2 Answers

0 votes

(a)

Step 1:

Concentration of silver chloride is [AgCl] = 10.0 M.

The solubility product of the two reactions are as follows.

image                 Solubility product image.

image             Solubility product: image.

image     Solubility product: image.

So the overall concentration of silver [Ag] is sum of the concentration of the silver used in the three reactions.

image

The overall reaction is image.

Solubility product of silver cholride in the overall reaction is image.

image

Solubility product is image.

Step 2:

Let x be the concentration image and image.

Then the concentration of the  image is 10-2x.

Solubility product image.

image

The solubility of the silver chloride in 10.0 M ammonia is 0.475 M.

Solution :

The solubility of the silver chloride in 10.0 M ammonia is 0.475 M.

answered May 1, 2015 by Lucy Mentor
edited May 1, 2015 by Lucy
0 votes

(b)

Step 1:

Concentration of silver chloride is [AgCl] = 10.0 M.

The overall reaction is image.

Let x be the concentration and image.

Then the concentration of the image is 10-2x.

The solubility of the silver chloride in 10.0 M ammonia x is 0.475 M.         (From (a))

Concentration of the image is .

Concentration of the image is 9.05 M.

Solution :

Concentration of the image is 9.05 M.

answered May 1, 2015 by Lucy Mentor

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