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Find standard form?????????

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Find equation of the line that passes through (9,-7) and (-3,5)

Write in standard form.

asked Mar 30, 2013 in ALGEBRA 2 by andrew Scholar

1 Answer

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The two  points passes through the line (9 , -7) and (-3 , 5)

The line slope is m = y2 - y1 / x2 - x1

Substitute x1 =9 , y1 =-7 , x2 =-3 and y2 =5

There fore m = 5 -(-7) / -3 - 9

Simplify

m = 12 / -12

m = -1

the slope m and point (x1,y1) then the equation of the line y - y1 = m(x - x1)

Substitute x1 = 9 , y1 = -7 and m = -1 in the equation of the line y - y1 = m(x - x1)

y - (-7) = -1(x - 9)

y + 7 = -x + 9

Add x to each side

x + y + 7 = x - x + 9

x+ y + 7 = 0 + 9

x + y + 7 = 9

Subtract 7 from each side

x + y + 7 - 7 = 9 - 7

x + y = 2.

 

answered Mar 30, 2013 by diane Scholar
Answer is correct. If you add some more information like standard form line equation is Ax + By = C will help the answer.

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