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physics question help please!!?

0 votes

A uniform electric field exists between two oppositely charged parallel plates connected to a 13.0V battery. The plates are separated by 7.00x10-4 m.

 

a) Determine the magnitude of the electric field between the plates

b) If a charge of -4.29x10-6 C moves from one plate to another, calculate the change in electric potential energy of the charge.

 

asked Nov 19, 2014 in PHYSICS by anonymous

2 Answers

0 votes

a)

Find the magnitude of the electric field between the plates by using the relation:

E = V/d

   = (13) / (7.00x10-4 )

   = 1.857x10^4  Volts/m

answered Nov 20, 2014 by bradely Mentor
0 votes

b)

Find the change in potential energy of the charge.by using the formula:

PE = qEd

   = (4.29x10-6 )(1.857x10^4) (7.00x10-4)

    = 55.77 x 10-6 J

answered Nov 20, 2014 by bradely Mentor

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