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Derivative of y= tan(3x^2) - sec(3x^2)?

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please show all steps and explian ,,, ty in advance!!!@#!@#!@3
asked Apr 5, 2013 in CALCULUS by angel12 Scholar

1 Answer

0 votes

y = tan(3x2) - sec(3x2)

Apply derivative to each side

dy / dx = d / dx[tan(3x2) - sec(3x2)]

Apply derivative difference rule

dy / dx = d / dx[tan(3x2)] - d / dx[sec(3x2)]

dy /dx = sec2(3x2) 6x - sec(3x2)tan(3x2)6x

Take out common term 6xsec(3x2)

dy / dx = 6xsec(3x2)[sec(3x2) - tan(3x2)].

 

answered Apr 5, 2013 by diane Scholar

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