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WAVES-DIRECTION-INTERFERENCE

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If some light passes through two slits, separated by 0.33 mm, and the first dark fringe is located 0.035° from the central antinode, the wavelength of the light is ___x10-7m.

asked Nov 25, 2014 in PHYSICS by anonymous

1 Answer

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Distance between two slits d is 0.33 mm = 0.33 * 10^-3 m

First dark fringe means m = 0.5

Angle of Diffraction θ is 0.035°

We know that Double slit interference Equation m λ = d sin θ

λ = d sin θ / m

λ = (0.33 * 10^-3 * sin(0.035) ) / (0.5)

λ = 4.0317 * 10^-7 m.

Therefore the wavelength of the light is 4.0317 * 10^-7 m.

answered Nov 25, 2014 by Lucy Mentor

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