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How many sec. for it to hit the ground using h=480-16t^2
asked Apr 10, 2013 in PHYSICS by Jose Rodriguez Rookie

2 Answers

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 I t to the hit the  ground

Make h= 0.

0 = 480 - 16t²

Factor.

0 = 16(30 - )

Set each by zero and solve for t.

30 - t² = 0

-t² = -30

t² = 30

t = √30 seconds.

answered Apr 10, 2013 by diane Scholar
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h = 480 - 16t^2

Substitute h = 0 since height will be zero when hit the ground.

0 = 480 - 16t^2

480 = 16t^2

divide each side by 16

480/16 = t^2

t^2 = 30

t = sqrt (30)

t = 5.4777 seconds

answered Apr 13, 2013 by Naren Answers Apprentice

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