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Solve the following system of equations.

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x-3y+3z=-6 (first eq) -3x+9y-9z=18 (sec eq) 2x-6y+6z=-12?

asked Apr 22, 2013 in ALGEBRA 2 by rockstar Apprentice

1 Answer

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x - 3y + 3z = -6        -(1)

-3x + 9y - 9z = 18  ---> divide each side by 3 ------> x - 3y + 3z = -6

2x - 6y + 6z = -12   -----> divide each side by 2 -----> x - 3y + 3z = -6

Three equations are parallel so no solution to the system of equations.

 

answered May 14, 2013 by Naren Answers Apprentice

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