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For what value(s) of the constant a is the function f continuous everywhere...?

0 votes

f(x)= {a(x^2-2a)        if x < 0

          a sqrt(x+4) -4  if x greater than or equal to 0

asked Jan 31, 2015 in CALCULUS by anonymous

1 Answer

0 votes

Step 1:

The function is image.

If the function is continuous, then the left hand limit is equal to right hand limit.

Consider left hand limit,

image

Consider right hand limit,

image

Step 2:

Find the values of a.

Left hand limit is equal to right hand limit.

image

Multiply each side with negative one.

image

Apply zero product property.

image and image.

image and image.

The function is continuous for image and image.

Solution:

The function is continuous for image and image.

answered Jan 31, 2015 by Sammi Mentor
edited Jan 31, 2015 by Sammi

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