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Find the center,transverse axis,vertices,foci,and asymptotes.Graph the equation.

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Find the center,transverse axis,vertices,foci,and asymptotes.Graph the equation.

x^2 - y^2 - 2x - 2y - 1 = 0
asked Feb 3, 2015 in PRECALCULUS by anonymous

1 Answer

0 votes

Step 1:

The equation is image.

Group the like terms.

image

Add 1 to each side.

image

Complete each square.

image

image

So the equation is in the standard form of the hyperbola.

Compare the above equation with .

The center of the hyperbola is image.

image

image

image

Step 2:

The hyperbola has a transverse axis parallel to axis.

The foci of the hyperbola is image.

The vertices of the hyperbola is image.

Find the points to form a rectangle.

image.

image.

The extensions of the diagonals of the rectangle are the asymptotes of the hyperbola

Asymptotes of the hyperbola are .

Substitute the values of in .

image

Asymptotes are image.

Step 3:

Graph :

(1) Draw the coordinate plane.

(2) Draw the equation of the hyperbola.

(3) Plot the foci and vertices.

(4) Form a rectangle containing the points image, image.

(5) Draw the asymptotes of the hyperbola.


image

Solution :

The center of the hyperbola is image.

The hyperbola has a transverse axis parallel to axis.

The vertices of the hyperbola is image.

The foci of the hyperbola is image.

Asymptotes of the hyperbola are image.

Graph of the hyperbola :

image

 

answered Feb 6, 2015 by joseph Apprentice
edited Feb 7, 2015 by bradely

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