Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,883 users

Equation of tangent line y = ln(x^2 + 1)

0 votes

at the point (1, ln2)?

asked May 27, 2013 in CALCULUS by angel12 Scholar
reshown May 27, 2013 by bradely

1 Answer

0 votes

y = log(x2 + 1)

Differenciate each side with respective x

dy / dx = 1 / (x2 + 1) [2x + 0]

            = 2x / x2 + 1

The slope of the tangent line m = 2x / x2 + 1 at point ( 1 , log2)

Therefore m = 2(1) / 1 + 1 = 2 / 2 = 1

The tangent line equation formula : y - y1 = m(x - x1)

Substitute m = 1 , x 1 = 1 and y1 = log2 in the above tangent line

y - log2 = 1(x - 1)

y - log2 = x - 1

Add 1 to each side

y  + 1 - log2 = x

x - y = 1 - log2

x - y = 1 - 0.3010

x - y = 0.699

x - y = 699 / 1000

1000x - 1000y = 699.

answered Jun 4, 2013 by diane Scholar

Related questions

...