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what expression is equal to

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tan A + cot A to csc A sec A?

trigonometric-identities

asked Jun 24, 2013 in TRIGONOMETRY by payton Apprentice

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1 Answer

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The given expression is tanA + cot A to csc A sec A

tanA + cot A = sinA / cosA + cosA /sinA

= sin²A + cos²A / sinA cosA [ sin²A + cos²A = 1 ]

= 1/ sinA cosA

= 1/sinA . 1/ cosA

= cscA secA

Therefore tanA + cot A = cscA sec A.

answered Jun 24, 2013 by goushi Pupil

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