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NEED HELP!! PERMUTATION PROBLEMS?

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1.) 3 lottery tickets are drawn from a total of 50.If the tickets will distributed to each of the 3 employees . How many simple events are there?

2.) If 4 persons enter a bus in which there are 10 vacant seats . How many ways are there for the 4 to be sealed?

asked Jun 28, 2013 in ALGEBRA 2 by payton Apprentice

2 Answers

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1) Given that 3 lottery tickets are drawn from a total of 50.

     The tickets will distributed to each of the 3 employees that means 3 tickets are distributed

      to 3 employees.

      The simple events are:

       1 ticket to each employee.

       1 ticket to one employee and 2 tickets to 2nd employee

        3 tickets to one employee

    

answered Jun 28, 2013 by joly Scholar
0 votes

2) Number of persons = 4

     Number of seats which are vacant = 10 seats

     Number of ways for the 4 persons to be seated = image

                                                                                = (10 * 9 * 8 * 7) / (4 * 3 * 2 * 1)

                                                                                = 30 * 7

                                                                                = 210

     Therefore in 210 ways 4 persons can be seated.

   

answered Jun 28, 2013 by joly Scholar

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