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Solve algebraically for x:

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(1/(x+3))-(2/(3-x))=(4/(x^2-9))
asked Oct 16, 2017 in ALGEBRA 1 by anonymous

1 Answer

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(1/(x+3))-(2/(3-x))=(4/(x^2-9))

Rearrange the equation.

(1/(x+3))-(2/-(x-3))=(4/(x^2-9))

(1/(x+3))+(2/(x-3))=(4/(x^2-9))

LCM of (x+3) and (x-3) is (x+3)(x-3)

((x-3)+2(x+3))/(x+3)(x-3) =(4/(x^2-9))

(3x+3)/(x+3)(x-3) =(4/(x+3)(x-3))

3x+3=4

3x =1

x=1/3

 

 

 

answered Oct 16, 2017 by homeworkhelp Mentor
reshown Oct 16, 2017 by bradely

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