Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

777,311 users

Partial Fraction Expansion

0 votes

asked Dec 26, 2017 in ALGEBRA 2 by MathGuy Novice

1 Answer

0 votes

The expression

[s^2 + s - 1] / [s(s + 1)] + 1/s

Consider 1st term

[s^2 + s - 1] / [s(s + 1)^2]   =   A/s + B/(s + 1) + C/(s + 1)^2  ------------> (T)

Take the LCM 

[s^2 + s - 1] / [s(s + 1)^2]   =   { A[s + 1)^2] + B[s(s + 1)] + Cs } / [ s(s + 1)^2 ]

[s^2 + s - 1]   =   { A[s^2 + 2s + 1)] + B(s^2 + s) + Cs }

[s^2 + s - 1]   =    As^2 + 2As + A + Bs^2 + Bs + Cs 

[s^2 + s - 1]   =    (A + B)s^2 + (2A + B + C)s + A 

Compare the coefficients of S^2, s and constant terms

A   =   - 1

A + B   =   1  -----------------------------> (1)

2A + B + C   =   1  --------------------------> (2) 

Substitute A  = - 1 in equation (1)

-1 + B   =   1

B   =   1 + 1

B   =   2

Substitute A  = - 1 and B  =  2 in equation (2)

2(-1) + 2 + C   =   1

-2 + 2 + C   =   1

C   =   1

Substitute A  = - 1, B  =  2 and C  =  1 in equation (T)

[s^2 + s - 1] / [s(s + 1)^2]   =   (-1/s) + 2/(s + 1) + 1/(s + 1)^2

Hence

[s^2 + s - 1] / [s(s + 1)] + 1/s   =   [ (-1/s) + 2/(s + 1) + 1/(s + 1)^2 ] + 1/s

[s^2 + s - 1] / [s(s + 1)] + 1/s   =    2/(s + 1) + 1/(s + 1)^2 

answered Dec 27, 2017 by homeworkhelp Mentor

Related questions

asked Feb 7, 2015 in ALGEBRA 2 by anonymous
asked Jul 18, 2014 in ALGEBRA 2 by anonymous
asked Jul 18, 2014 in ALGEBRA 2 by anonymous
...