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Write the equation of the line that is perpendicular to the line

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y = 2x + 2 and passes through the point (6, 3).

asked Jul 4, 2013 in ALGEBRA 2 by anonymous Apprentice

1 Answer

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The given line equation is  y = 2x+2  and passes throogh the point (6, 3)

compare it with slope intercept form line equation y = mx + c . m = slope.

m =2

The lines are perpendicular so new line slope = -1/m = -1/2

The line equation in point slope form is y - y1 = m (x - x1)

y - 3 = -1/2 ( x -6)

2(y -3) = -1(x - 6)

2y - 6 = -x+6

-x - 2y = 12

x +2y = -12.

answered Jul 4, 2013 by goushi Pupil

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