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(x+2)^2+(y-2)^2=4 / Write in general form

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I have figured how to get it into radius form but now I am lost about general form.. my original points were

(-2,4) (0,2) (-2,0) (-4,2)

(x-h)^2+ (y-k)^2=r^2

which I got my original answer of (x+2)^2+(y-2)^2=4, but I cannot seem to understand how to get it into general form.
related to an answer for: general form of (x-2)^2 + (y-4)^2 =36
asked Sep 28, 2018 in ALGEBRA 2 by anonymous
reshown Sep 28, 2018 by bradely

1 Answer

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Given Equation of The Circle 

(x + 2)^2 + (y - 2)^2  =  4

Expand them

(x^2 + 4x + 4) + (y^2 - 4y + 4)  =  4

x^2 + 4x + 4 + y^2 - 4y + 4 - 4  =  0

x^2 + y^2 + 4x - 4y + 4  =  0

Answer :

Genral form is x^2 + y^2 + 4x - 4y + 4  =  0.

answered Sep 29, 2018 by homeworkhelp Mentor

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