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Solve the following radical equations

0 votes

Solve the following radical equations

asked Oct 13 in ALGEBRA 2 by anonymous

1 Answer

0 votes

457)

√(3x + 4) + 8   =   12

√(3x + 4)   =   12 - 8

√(3x + 4)   =   4

Apply square on each side

(3x + 4)   =   4^2

(3x + 4)   =   16

3x  =  16 - 4

3x  =  12

x  =  12/3

x  =  4

458)

√(5x - 4) + 3   =   12

√(5x - 4)   =   12 - 3

√(5x - 4)   =  9

Apply square on each side
 
(5x - 4)   =  9^2
 
5x - 4   =  81
 
5x   =  81 + 4
 
5x  =  85
 
x  =  85/5
 
x  =  17
 
459)
 
√(4x + 9)   =   - 13
 
Apply square on each side
 
4x + 9   =   (- 13)^2
 
4x + 9   =   169
 
4x  =  169 - 9
 
4x  =  160
 
x  =  160/4
 
x  =  40
 
Answer :
 
457)  x  =  4
 
458)  x  =  17
 
459)  x  =  40.
answered Oct 14 by homeworkhelp Mentor

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