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solve for v^2

0 votes
LA=LB square root of 1-v^2/c^2
asked Nov 20, 2014 in ALGEBRA 2 by doan12345 Pupil

1 Answer

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The equation LA = LB√[(1 - v2)/c2]

Cancel common terms.

A = B√[(1 - v2)/c2]

Squaring on each side.

A2 = B2[(1 - v2)/c2]

A2 = [B2(1 - v2)]/c2

Multiply each side by c2.

A2c2 = B2(1 - v2)

Divide each side by B2.

(A2c2)/B2 = 1 - v2

Subtract 1 from each side

(A2c2)/B2 - 1 = - v2

Multiply each side by negative one.

v2 = 1 - (A2c2)/B2.

answered Nov 20, 2014 by david Expert

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