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Explain these problems please!!?

0 votes
I'm soo confused!!! :
1. 5a^-3b^4/15cd^-2

2. 8x^-2y^4z^-3
asked Jan 8, 2013 in PRE-ALGEBRA by futai Apprentice
reshown Jan 8, 2013 by bradely

4 Answers

0 votes

1. 5a^-3b^4/15cd^-2

( 5a-3 b4 ) / ( 15cd-2 )                                      (a-1=1/a)

So , ( 5 ( 1/a3 ) b4 ) / ( 15c(1/d2) )

Simplfy    

( 5b4 / a3) / ( 15c / d2)                                 ( a/b ) / ( c/d )= ( ad / bc )

( 5b4 / a3) * ( d2/15c )

( 5 b4 d2 ) / ( 15c a3)

There fore   ( 5 b4 d2 ) / ( 15c a3)

answered Jan 9, 2013 by richardson Scholar

5b4 d2 / 15c a3

= b4 d2 / 3c a3

0 votes

2. 8x^-2y^4z^-3

= 8x-2y4z-3                               (a-1=1/a)

= 8( 1/x2 )y4 ( 1 / z3 )

Simplfy  

= 8 y4 ( 1 / x2z3)

Simplfy 

=( 8 y4 / x2 z3 )

 there fore ( 8 y4 / x2 z3 )

answered Jan 9, 2013 by richardson Scholar
0 votes

1. 5a^-3b^4/15cd^-2

( 5a-3 b4 ) / ( 15cd-2 )                                      (a-1=1/a)

So , ( 5 ( 1/a3 ) b4 ) / ( 15c(1/d2) )

Simplfy    

( 5b4 / a3) / ( 15c / d2)                                 ( a/b ) / ( c/d )= ( ad / bc )

( 5b4 / a3) * ( d2/15c )

( 5 b4 d2 ) / ( 15c a3)

(b^4d^2) / 3ca^3

There fore  b^4d^2) / 3ca^3

 

answered Jan 10, 2013 by krish Pupil
0 votes

1. 5a^-3b^4/15cd^-2

( 5a-3 b4 ) / ( 15cd-2 )                                      (a-1=1/a)

So , ( 5 ( 1/a3 ) b4 ) / ( 15c(1/d2) )

Simplfy    

( 5b4 / a3) / ( 15c / d2)                                 ( a/b ) / ( c/d )= ( ad / bc )

( 5b4 / a3) * ( d2/15c )

( 5 b4 d2 ) / ( 15c a3)

Simplfy

( b4 d2 ) / ( 3 c a3)

There fore

( 5a-3 b4 ) / ( 15cd-2 ) = ( b4 d2 ) / ( 3 c a3)

answered Jan 10, 2013 by richardson Scholar

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