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Find the slope of a line that is parallel and perpendicular to the given line. 10 pts please explain.?

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1. y = 3/5x - 8
2. y = -3x + 1
asked Nov 9, 2013 in ALGEBRA 1 by dkinz Apprentice

1 Answer

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General form of slope intercept form of line is y = mx + c

Here slope = m and y-intercept = c

1)y = 3/5 x - 8

Here slope m1 = 3/5

If two lines are parallel then the required line slope is m2 = m1

Therefore parallel slope is m2 = 3/5

If two lines are perpendicular then the required line slope is m2 = -1/m1

Therefore perpendicular slope is m2 = -1/(3/5)

                                                           = -5/3

2)y = -3x + 1

Here slope m1 = -3

If two lines are parallel then the required line slope is m2 = m1

Therefore parallel slope is m2 = -3

If two lines are perpendicular then the required line slope is m2 = -1/m1

Therefore perpendicular slope is m2 = -1/(-3)

                                                          = 1/3


 

answered Nov 11, 2013 by jouis Apprentice

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