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Algebra II Area Problem?

0 votes

Find the dimensions of a rectangle if the area is 50m^2, the width is x-3, and the length is x+2.

asked Jan 9, 2013 in ALGEBRA 2 by homeworkhelp Mentor

1 Answer

+1 vote

area is 50m2,

the width is x-3,

and the length is x+2.

Then area of the rectangle =  ( x-3 )(x+2) = 50

There fore

x2+2x-3x-6 = 50

Simplfy

x2-x-6 = 50

Subtract 50 from each side.

x2- x - 6 -50 = 50 - 50

x2- x - 56 = 0

x2- 8x +7x - 56 = 0

Take out common factors.

x( x-8 ) +7( x-8) = 0

Take out common factors.

( x+7)( x-8 ) = 0

There fore

x+7 = 0  or  x-8 = 0

x =-7 or x = 8

There fore  x = -7 or  8

answered Jan 9, 2013 by richardson Scholar

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