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(4x^2 - 9) divide (2x - 3)

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(4x^2 - 9) divide (2x - 3)

real-numbers

asked Nov 23, 2013 in ALGEBRA 1 by rockstar Apprentice

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1 Answer

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(4x^2-9)

This is in a^2-b^2 form.

here a = 2x, b = 3

We can also write it (2x-3)(2x+3)

There fore (2x-3)(2x+3)/(2x-3)

Cancel the same terms.

= 2x+3

So (4x^2-9)/(2x-3) = 2x+3

answered Nov 23, 2013 by william Mentor

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