Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,216)
GEOMETRY (864)
ALGEBRA 2 (2,745)
TRIGONOMETRY (1,186)
PRECALCULUS (1,903)
CALCULUS (2,791)
STATISTICS (129)
PHYSICS (658)
CHEMISTRY (136)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration substitution-method limits calculus

13,435 questions

17,804 answers

1,438 comments

777,589 users

sin2x+cos x=cos x(2sinx+1)

0 votes

i need this to be verified please

trigonometric-identities

asked Nov 30, 2013 in TRIGONOMETRY by futai Scholar

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

We know that sin2A = 2sinA cosA

left hand side = sin2x+cosx

= 2sinxcosx +cosx

= cosx(2sinx+1)

= right hand side

answered Nov 30, 2013 by william Mentor

Please log in or register to add a comment.

Related questions

Prove cos^2(45 degrees+x)-sin^2(45degrees+x)= -sin2x?

asked Aug 22, 2015 in TRIGONOMETRY by anonymous

trigonometric-functions
trigonometric-identities

verify that that square root of (1-cos(x)/1+cox(x)) = sin(x)/1+cox(x)

asked Dec 5, 2013 in TRIGONOMETRY by chrisgirl Apprentice

trigonometric-identities

Prove cos^6x-sin^6x=cos2x-1/8sin4xsin2x?

asked Aug 22, 2015 in TRIGONOMETRY by anonymous

trigonometric-identities

solve: 2(sin^4x + cos^4x) = 1

asked Mar 8, 2014 in TRIGONOMETRY by rockstar Apprentice

trigonometric-identities
solve-trigonometric-equations

cos^4x - sin^4x = 1-2sin^2x

asked Feb 24, 2014 in TRIGONOMETRY by futai Scholar

trigonometric-identities

Tan s / 1 + cos s + sin s / 1 - cos s = cot s + sec s csc s

asked Nov 30, 2013 in TRIGONOMETRY by chrisgirl Apprentice

trigonometric-identities

Show cos 20 * cos 40 * cos 80 =1/8

asked May 27, 2013 in TRIGONOMETRY by andrew Scholar

trigonometric-identities

cos(x + y) cos(x − y) = cos2 x − sin2 y

asked Mar 10, 2014 in TRIGONOMETRY by harvy0496 Apprentice

trigonometric-identities
trigonometric-equation

find x: (sin^2 x)(tan x) = 2 - cos^2 x

asked Mar 4, 2014 in TRIGONOMETRY by andrew Scholar

trigonometric-identities

Verify the identity: cos x + sin x tan x = sec x.

asked Nov 20, 2013 in TRIGONOMETRY by andrew Scholar

trigonometric-identities

area between y=sin2x and y=2sinx

asked Jan 16, 2017 in CALCULUS by anonymous

area

How do you verify that cos^2x(sec^2x-1)=sin^2x?

asked May 1, 2014 in ALGEBRA 2 by anonymous

trigonometric-identities

If θ is in quadrant II and cos θ = − 2/3

asked Dec 22, 2017 in TRIGONOMETRY by anonymous

double-angle
trigonometric-identities

prove: sinθ cosθ = (cosθ - cos^3θ)/sinθ

asked Mar 10, 2014 in TRIGONOMETRY by dkinz Apprentice

trigonometric-identities
solving-trigonometric-equations

prove that 2(sin 6x + cos 6x) - 3(sin 4x + cos 4x) = 0

asked Nov 30, 2013 in TRIGONOMETRY by linda Scholar

trigonometric-identities

Math question. tan(x)=-1 and tan(y)=2 find tan(x+y) and tan(x-y)?

asked Nov 26, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

Let X and Y are real numbers such that sinX/sinY = 3 and cosX/cosY = 1/2.

asked Jun 24, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

1/sec x tan x=csc x-sin x

asked Apr 15, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

Tan x/2 = (1-cosx+sinx)/(1+cosx+sinx) prove this?

asked Feb 11, 2014 in TRIGONOMETRY by futai Scholar

trigonometric-identities

if sinθ = 1/2(x+1/x), show that sin 3θ + 1/2 (x^3 + 1/x^3) = 0

asked Nov 30, 2013 in TRIGONOMETRY by skylar Apprentice

trigonometric-identities

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...