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Solve by the elimination method 2a+9b=52 , -2a+b=8 The solution is (type an ordered pair)

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Solve by the elimination method
2a+9b=52
-2a+b=8
The solution is    (type an ordered pair)
asked Dec 2, 2013 in ALGEBRA 1 by rockstar Apprentice

1 Answer

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Elimination method

2a+9b = 52 --------> (1)

-2a+b = 8 -----------> (2)

To eliminate the a value , add the equations (1) and(2).

2a+9b = 52

-2a+b = 8

__________

10b = 60

Divide to each side by 10.

10b/10 = 60/10

b = 6

Substitute the b value in equation (1).

2a+9*6 = 52

2a+54 = 52

Subtract to each side by 54.

2a+54-54 = 52-54

2a = -2

Divide to each side by 2.

2a/2 = -2/2

a = -1

The solution is (a,b) = (-1, 6)

 

answered Dec 2, 2013 by william Mentor

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