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How do I solve x - 8 + 3x + 2 < -6(8x - 7) + 4(8x - 2)

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I am having a issue with the positive and negative signs

multi-step-inequalities

asked Dec 6, 2013 in ALGEBRA 1 by payton Apprentice

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1 Answer

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x-8+3x+2 < -6(8x-7)+4(8x-2)

4x-6 < -48x+42+32x-8

4x-6 < -16x+34

Add 6,16x to each side.

4x+16x+6-6 <-16x+16x+ 34+6

20x < 40

Divide to each side by 20.

20x/20 < 40/20

Solution x < 2

answered Dec 6, 2013 by william Mentor

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