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Solve the system of equations 2x-3y=5 and 4x+y= 3

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Solve the system of equations 2x-3y=5 and 4x+y= 3

asked Dec 7, 2013 in ALGEBRA 1 by mathgirl Apprentice

1 Answer

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Elimination method

Given equation 2x-3y = 5

Multiple to each side by negitive 2

-4x+6y = -10 --------> (1)

And 4x+y = 3 -------> (2)

To eliminate the x value add the equations (1) and (2).

-4x+6y = -10

4x+y = 3

__________

7y = -7

Divide to each side by 7.

7y/7 = -7/7

y = -1

Substiute the y value in (1).

-4x+6*-1= -10

-4x-6 = -10

-4x = -10+6

-4x = -4

x = -4/-4

x = 1

Solution x = 1, y = -1.

answered Dec 7, 2013 by william Mentor

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