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solve the simultaneous equation 2x+5y=1,3x-2y=30

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asked May 4, 2014 in ALGEBRA 1 by anonymous

1 Answer

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Substitution method :

The equations are 2x + 5y = 1 and 3x - 2y = 30.

Solve equation 2x + 5y = 1, and solve for x.

2x = 1 - 5y

⇒ x = ( 1 - 5y )/2.

Substitute the value x = ( 1 - 5y )/2 in 3x - 2y = 30, and solve for y.

3[ ( 1 - 5y )/2 ] - 2y = 30

3 - 15y - 4y = 60

3 - 19y = 60

19y = 3 - 60 = - 57

⇒ y = - 57/19 = - 3.

Substitute the value y = - 3 in x = ( 1 - 5y )/2, and solve for x.

x = ( 1 - 5(- 3) )/2

x = ( 1 -+ 15 )/2 = 16/2

⇒ x = 8.

The solution of the simultaneous equations are x = 8 and y = - 3.

answered May 5, 2014 by lilly Expert

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