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Solve 4x^2-8x+3?

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Please help solving

4x^2-8x+3=0

roots-of-polynomials

asked May 10, 2014 in ALGEBRA 1 by anonymous

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1 Answer

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The quadratic equation is 4x ^2 - 8x + 3 = 0

4x ^2 - 6x - 2x + 3 = 0

2x(2x - 3) -1 (2x - 3) = 0

(2x - 3) (2x - 1) = 0

Apply zero product property.

2x - 3 = 0 and 2x - 1 = 0

2x = 3 and 2x = 1

x = 3/2 and x = 1/2

Solution x = 3/2 and 1/2.

answered May 10, 2014 by david Expert

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