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TriangleABC has vertices A(10,8) B(-2,10) and C(2,4). Classify the triangle.

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Determine the perimeter of the triangle?

asked Jul 22, 2014 in GEOMETRY by anonymous

1 Answer

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The vertices are A(10, 8), B(-2, 10) and C(2, 4).

Length of the side AB = √[(10 - (-2))2 + (8 - 10)2] = √[(12)2 + (-2)2] = √[144 + 4] = √148.

Length of the side BC = √[(-2 - 2)2 + (10 - 4)2] = √[(-4)2 + (6)2] = √[16 + 36] = √52.

Length of the side AC = √[(10 - 2)2 + (8 - 4)2] = √[(8)2 + (4)2] = √[64 + 16] = √80.

Perimeter of the triangle = AB + BC + AC

= √148 + √52 + √80

= √[4(37)] + √[4(13)] + √[16(5)]

= 2√(37) + 2√(13) + 4√(5)

= 2(6.08) + 2(3.6) + 4(2.23)

= 12.16 + 7.2 + 8.94

= 28.3 units.

 

answered Jul 24, 2014 by joly Scholar

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