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Find the sides of the triangle

0 votes

asked Aug 5, 2014 in PRECALCULUS by anonymous
reshown Aug 5, 2014 by bradely

1 Answer

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Draw the geometric diagram

From ∆BDC

sinθ =BD/BC

BC =BD/sinθ

    =5/sinθ

Opposite angles are equal

∠ABF =θ

rom triangle ABF

cosθ =BF/AB

AB =BF/cosθ

    =4/cosθ

AC =AB+BC

     = 4/cosθ +5/sin θ

    

answered Aug 5, 2014 by bradely Mentor

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