# What is 6x^3-5x^2+x+1

Given polynomial is 6x³-5x²+x+1

Dvisior x +2

Use synthetic division to find (6x³-5x²+x+1) ÷ (x +2)

The dividend is 6x³-5x²+x+1, and the root is -2.

Step 1 : Write the terms of the dividend so that the degrees of the terms are in descending order. Then write just the coefficients as shown below.

Step 2 : Write the constant r of the divisor (x + r) to the left. In this case, r = -2. Bring the first coefficient 6 down.

Step 4 :Multiply the first coefficient by r : 6 × -2 = -12

Write the product under the second coefficient, -5 and add : -5 -12 = -17.

Step 5 : Multiply the sum -17 by r : -17 × -2 = 34.

Write the product under the next coefficient, 1 and add : 1 + 34 = 35.

Step 6 : Multiply the sum 35 by r : 35 × -2 = -70.

Write the product under the next coefficient, 1 and add : 1 - 70 = -69. The remainder is -69.

The numbers along the bottom row are the coefficients of the quotient. Start with the power of x that is one less than the degree of the dividend. Thus, the quotient is 6x² -17x +35 .

Quotient  is 6x² -17x +35 and remainder is -69.