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Describe the domain and range of the function:

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F(x) = - Sq.rt.of.x+1.?
asked Nov 11, 2014 in ALGEBRA 2 by anonymous

1 Answer

0 votes

The function f(x) = - √(x + 1)

Index of the function is 2.

2 is even number.

x + 1 ≥ 0

x ≥ - 1

Domain set is { x ∈ R : x ≥ - 1}

Range set is the corresponding y values of the function for different values of x.

The negative sign in front of the radical in this function.

Since for all non negative real numbers of x , the function is ≤ 0.

For example the first domain value is - 1, then y = -(x + 1)1/2  = -(- 1 + 1)1/2 = 0, so the range value starting with 0.

So, the range of the function is always less than or equal to 0.

Range set is{ y ∈ R : y ≤ 0}.

answered Nov 11, 2014 by david Expert

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