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Determine the values of m and n

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Determine the values of m and n when 2x^3 -mx^2 + nx -2 is divided by x +1, the remainder is -12 and x-2 is a factor

asked Sep 8, 2018 in ALGEBRA 2 by mathgirl Apprentice
reshown Sep 8, 2018 by bradely

1 Answer

0 votes

Let f(x)  =  2x^3 -mx^2 + nx -2 ----------> (1)

if (x - 2) is factor of f(x) then f(2) = 0

Substitute x = 2 in f(x)

f( 2 )  =  2(2)^3 -m(2)^2 + n(2) -2
0  =  2(8) -m(4) + 2n -2                                   [ Since f(2)  =  0 ]

0  =  16 - 4m +2n -2

4m - 2n  =  14----------------------> (2)

if f(x) is devisable by (x + 1) then f(-1) = R     [ R stands for remainder ]

Substitute x = -1 in f(x)

f( -1 )  =  2(-1)^3 -m(-1)^2 + n(-1) -2
-12  =   2(-1) - m(1) - n - 2                              [ Since f(-1)  =   R  =  -12 ]
 
 
-12  =   -2 - m - n - 2
m + n  =  -4 + 12
m + n  = 8 -------------------> (3)
 
Multiply Eq (3) with 2 and to Eq (2)
Eq (3) X 2 =====>  2m + 2n  =  16
Eq (2) ========>  4m - 2n  = 14
                           ________________
                                6m + 0  =  30
                                     6m   =  30
                                       m   =  30/6
                                       m   =  5
Substitute m = 5 in Eq (3)
5 + n  =  8
n  =  8 - 5
n  =  3.
 
Answer :

Solution is m = 5 and n  =  3..

answered Sep 8, 2018 by homeworkhelp Mentor

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