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how to I find the zeros of 5y^3-3y^2+8y=0?

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Please help me answer this. It is a poly nomial function. I need to find the zeros.

asked Dec 6, 2013 in ALGEBRA 1 by angel12 Scholar

1 Answer

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Given polynomial is 5y^3-3y^2+8y = 0

By the rational root therom

q is leading coefficient a n, p is constant term a 0.

If p/q is a rational zero.

Leading coefficient is 5,any rational zero must be a divisor of the constant term 0.

So the possible ratiional zero is 0.

P(0) = 0

Rational zeros of given polynomial is y = 0.

answered Dec 27, 2013 by david Expert

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