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what is the area of a simicircle, with an base of 14mm, and a height of 2mm.

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area of a simicircle.
asked Mar 12, 2014 in GEOMETRY by payton Apprentice

1 Answer

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Here base means diameter of semicircle (d ) = 14mm.

d = 2r r = d/2 r = d/2 = 14/2 = 7 mm.

Area of a semicircle (A ) = πr 2/2.

Substitute the values  π = 3.14 and r  = 7.

A = (3.14)(7) 2/2

    = 3.14 * 49 / 2

    = 76.93.

Therefore, area of a semicircle is 76.93 mm ^2.

answered Mar 28, 2014 by lilly Expert

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