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Select the point that lies on the graph of y > -3x + 4.?

0 votes
A.(-1, 7)
B.(0, 3)
C.(1, 3)
D.(3, -6)
asked Feb 2, 2013 in ALGEBRA 1 by anonymous Apprentice

1 Answer

+1 vote

Graph the inequlaity y > -3x  +4. and locate the points

 

Inequlaity y > -3x  +4 Graph

 

Check the point which lies on the shaded region.

Point C(1. 3) lies on the shaded region.

Point (1, 7) lies on the border but the inequality symbol is >, so the points on the line are not included in the solution set.

 

answered Feb 2, 2013 by steve Scholar

The inequality is y > - 3x + 4.

  • A. (- 1, 7).

Substitute the values of (x, y) = (- 1, 7) in y > - 3x + 4.

7 > - 3(- 1) + 4

7 > 3 + 4

7 > 7.

The above statement is false.

So, the point (- 1, 7) does not lies on the graph of y > - 3x + 4.

  • B. (0, 3).

Substitute the values of (x, y) = (0, 3) in y > - 3x + 4.

3 > - 3(0) + 4

3 > 0 + 4

3 > 4.

The above statement is false.

So, the point (0, 3) does not lies on the graph of y > - 3x + 4.

  • C. (1, 3).

Substitute the values of (x, y) = (1, 3) in y > - 3x + 4.

3 > - 3(1) + 4

3 > - 3 + 4

3 > 1.

The above statement is true.

So, the point (1, 3) lies on the graph of y > - 3x + 4.

  • D. (3, - 6).

Substitute the values of (x, y) = (3, - 6) in y > - 3x + 4.

- 6 > - 3(3) + 4

- 6 > - 9 + 4

- 6 > - 5.

The above statement is false.

So, the point (3, - 6) does not lies on the graph of y > - 3x + 4.

 

Option C is the correct choice.

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