Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

  
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,849 users

Write the equation of the circle with the given center and length of a radius

0 votes
Center at (3,5) and r=2
Thanks.
asked Mar 17, 2014 in ALGEBRA 2 by linda Scholar

2 Answers

–1 vote

Circle equation is (x - h)^2 + (y - k)^2 = r^2

Center (h, k) = (3, 5) and r = 2

Substitute (h, k) = (3, 5) and r = 2 in (x  - h)^2 + (y - k)^2 = r^2

(x - 3)^2 + (y - 5)^2 = 2^2

x^2 - 6 + 9 + y^2 - 10y  + 25 = 4

x^2 + y^2 - 6x - 10y  + 25 = 4

Subtract 4 from each side.

x^2 + y^2 - 6x - 10y  + 25 - 4 = 0

x^2 + y^2 - 6x - 10y  + 21 = 0.

Required circle equation is

x^2 + y^2 - 6x - 10y  + 21 = 0.

answered Mar 18, 2014 by dozey Mentor
+1 vote

Circle equation is (x - h)^2 + (y - k)^2 = r^2

Center (h, k) = (3, 5) and r = 2

Substitute (h, k) = (3, 5) and r = 2 in (x  - h)^2 + (y - k)^2 = r^2

(x - 3)^2 + (y - 5)^2 = 2^2

x^2 - 6 + 9 + y^2 - 10y  + 25 = 4

x^2 + y^2 - 6x - 10y  + 34 = 4

Subtract 4 from each side.

x^2 + y^2 - 6x - 10y  + 34 - 4 = 0

x^2 + y^2 - 6x - 10y  + 30 = 0.

Required circle equation is

x^2 + y^2 - 6x - 10y  + 30 = 0.

answered Mar 18, 2014 by dozey Mentor

Related questions

...