Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

781,696 users

Find the equation of a circle whose center is at the point (-2 , 3) and its diameter has a length of 10.

0 votes
Find the equation of circle
asked Oct 21, 2018 in ALGEBRA 2 by anonymous
reshown Oct 21, 2018 by bradely

1 Answer

0 votes

Center of the circle is (-2, 3)

Diameter  =  10

Radius (r) =  10/2  =  5

The standard form of the circle equation is ( x - h )2 + ( y - k )2 = r2, where, (h, k) is the center of the circle, and is the radius.

Substitute (h, k)  =  (-2, 3)  and r  =  5 in above standard form

(x + 2)^2  +  (y - 3)^2  =  5^2

x^2 + 4x + 4  +  y^2 - 6y + 9  =  25

x^2 + 4x + 4  +  y^2 - 6y + 9 - 25  =  0

x^2  +  y^2 + 4x - 6y - 12  =  0

Answer :

The equation of the circle is x^2  +  y^2 + 4x - 6y - 12  =  0.

answered Oct 21, 2018 by homeworkhelp Mentor

Related questions

...