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Differentiate with respect to x

+4 votes

 

f(x) = x^3 - 2x^2 - 5x - 12 / 4x^2 - 9?

asked Feb 3, 2013 in CALCULUS by anonymous Apprentice

1 Answer

+3 votes

f(x) = x^3 - 2x^2 - 5x - 12 / 4x^2 - 9

Recall the quotient rule d/dx(u/v)= [ u'·v -u·v' ] / v2(x)

Here u = x3-2x2-5x-12;v = 4x2-9

u'(x) =3x2-4x-5;v'(x) =8x

f'(x)=(3x2-4x-5)(4x2-9)-(x3-2x2-5x-12)(8x)/(4x2-9)^2

           =12x4-27x2-16x3-36x-20x2+45-8x4+16x3-40x2-96x/16x4-72x2+81

        =4x4-87x2-132x+45/16x4-72x2+81

The derivative of the given function is 4x4-87x2-132x+45/16x4-72x2+81

Hope that helps u

 

answered Feb 3, 2013 by bradely Mentor

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