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What is the radius of the circle whose equation is x^2+ y^2 = 8?

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how would you go about solving this

asked Apr 23, 2014 in PRECALCULUS by anonymous

1 Answer

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The equation is x^2+y^2 = 8.

Rewrite the equation as x^2 + y^2 = (√8)^2.

Compare the above equation with standard form of a circle (x - h)^2 + (y - k)^2 = r^2, where, center (h, k) = (0, 0) and radius = r.

Center (h, k) = (0, 0) and radius (r) = √8.

Therefore, radius of the circle is √8.

answered Apr 23, 2014 by lilly Expert

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