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Solve the initial value problem...?

+1 vote
dy/dx = 12 sin^2 x cos x, y(0)=4
asked Feb 8, 2013 in CALCULUS by andrew Scholar

1 Answer

+1 vote

dy/dx=12 sin2x cos x

Multiply each side by 'dx'.

dy = (12 sin2x cos x)dx

Apply integral each side.

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Integrals with Trigonometric Functions formula: 

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Given that y(0) = 4.

4 = 4[sin(0)]3 + c

4 = 0 + c

Therefore c = 4

y = 4(sin3x) + 4.

answered Feb 8, 2013 by richardson Scholar

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