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15-(5*Y+6)/2+2=4?

asked Jun 7, 2014 in ALGEBRA 2 by anonymous

1 Answer

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The equation is 15 - (5*Y + 6)/2 + 2 = 4 and solve for Y.

Combine constant trems as 15 and 2.

17 - (5*Y + 6)/2 = 4

Subtract 17 from each side.

17 - (5*Y + 6)/2 - 17 = 4 - 17

- (5*Y + 6)/2 = - 13

Multiply each side by negative 2.

[-(5*Y + 6) / 2]*(- 2) = (- 13)*(- 2)

5*Y + 6 = 26

Subtract 17 from each side.

5*Y + 6 - 6 = 26 - 6

5*Y = 20

Divide each side by 5.

(5*Y)/5 = (5*4)/5

Cancel common terms.

Y = 4.

The value of Y = 4.

answered Jun 7, 2014 by steve Scholar

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