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How to find the solution of this inequality (log) ?

0 votes

(1/3)^(2x+1) < [27/3^(x-1)]

solving-inequalities

asked Jun 10, 2014 in ALGEBRA 2 by anonymous

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1 Answer

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The exponential inequality is .

Rewrite 27 as 3³.

.

Apply power of a quotient property :

.

.

Apply Property of Inequality for Exponential Functions : Let b > 1. Then b^x < b^y if and only if x < y.

Add 2x to each side.

Subtract 4 from each side.

.

The solution set is .

answered Jun 10, 2014 by casacop Expert

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