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Algebra Based Physics Hw Help?

+2 votes

A 4.47 kg block initially at rest is pulled to the right along a horizontal surface by a constant, horizontal force of 15.4 N. The coefficient of kinetic friction is 0.133.
The acceleration of gravity is 9.8 m/s2 .
Find the speed of the block after it has moved 3.39 m.

asked Feb 16, 2013 in PHYSICS by anonymous Apprentice

1 Answer

+2 votes
Best answer

Let us draw the free-body diagram of the block,


To calculate normal force using equilibrium equation in y-direction





Here m is the mass and g is the acceleration due to gravity.

Substitute m=4.47 kg and g=9.8 m/s^2 in above equation,

N=4.47x9.8=43.806 N


Frictional force,Ff=μkN

μk=Coefficient of kinetic friction

Ff=0.133x43.806=5.826 N

Using almbert principal in x-direction



a=5.826/4.47=1.3034 m/s^2


Using motion equation




v=2.973 m/s

speed of the block after it has moved 3.39 m.is 2.973 m/s


I hope that helps u





answered Feb 16, 2013 by bradely Mentor
selected Feb 17, 2013 by anonymous
thank u very much

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