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Help With Interval Inequality?

+2 votes

Help With Interval Inequality?

Solve the inequality; Put the answer in interval notation . type infinity . For more than one interval use a U to represent a " union ". Write () if there is no solution.

1) 55x^2 + 26x-56<0

2) (11x+4)(5x-4)<2511

3) (3x+2)(5x-10) >55

4) (x+11) / (x-8)(x-30) ≤ 0

5) (38x-18)(x-16) / (x-35)^2 > 0

6) x / (x-9) > 342 / 71
asked Feb 19, 2013 in ALGEBRA 1 by dkinz Apprentice

11 Answers

0 votes

6) The inequality is image

  • Step-1

State the exclude values,These are the values for which denominator is zero.

The exclude value of the inequality is 9.

  • Step - 2

Solve the related equationimage

image

image

image

image

image

image

image

Solution of related equation image

  • Step - 3

Draw the vertical lines at the exclude values and at the solution to separate the number line into intervals.

  • Step - 4

Now test  sample values in each interval to determine whether values in the interval satisify the inequality.

Test interval     x - value      Inequality                                Conclusion

(-∞, 9)               x = 8            image         False

(9, 3078/271)     x = 10          image         True

(3078/271, ∞)   x = 12          image           False

The above conclude that the inequality is satisfied for all x - values in (9, 3078/271).

Note that the original inequality contains a “greater than” symbol. This means that the solution set does not contain the endpoints of the test interval (9, 3078/271).

The solution of the inequality image is 9 < x < 3078/271

The interval notation from of solution is (9, 3078/271).

answered Jun 4, 2014 by david Expert
edited Jun 4, 2014 by david

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