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Identify the 27th term of an arithmetic sequence

0 votes

where a1=38 and a17=-74?

asked Dec 27, 2012 in ALGEBRA 1 by angel12 Scholar

2 Answers

0 votes

a17=a1+(n-1)d

      =38+(17-1)d

-74=38+16d

-74-38=16d

-112=16d

d= -7

 the term 27 ; a27=a1+(n-1)d

a27=38+(27-1)(-7)

a27=38+26*(-7)

a27=38-182

a27= -144

27th term of arithmetic sequence a27= -144

 

 

 

answered Dec 27, 2012 by ricky Pupil
0 votes

Given a1=38,a17=-74

a17=a1+(n-1)d

      =38+(17-1)d

-74=38+16d

-74-38=16d

-112=16d

d= -7

 the term 27 ; a27=a1+(n-1)d

a27=38+(27-1)(-7)

a27=38+26*(-7)

a27=38-182

a27= -144

27th term of arithmetic sequence a27= -144

 

 

 

answered Dec 27, 2012 by ricky Pupil

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