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Given that sinA 5/8 and that <A is located in the second quadrant , determine exact value for the other two primary trigonometric ratios. including sketch pls
asked Oct 2, 2014 in CALCULUS by anonymous

1 Answer

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The trigonometric function value of sin(A) = 5/8.

To find the value of cos(A), using the Pythagorean identity : sin2(θ) + cos2(θ) = 1, we obtain

(5/8)2 + cos2(A) = 1

cos2(A) = 1 - 25/64 = 39/64.

Because cos(A) < 0 in quadrant II, we can use the negative root to obtain

cos(A) = - √39/√64 = - √39/8.

Using the Quotient identity : tan(A) = sin(A)/cos(A), we obtain

tan(A) = (5/8) / (- √39/8) = - 5/√39.

Graph :

answered Oct 2, 2014 by casacop Expert
edited Oct 2, 2014 by casacop

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