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please help need tom

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The point (-5,8) is located on the terminal arm of <A in standard position

a. sketch

b. determine the measure of <A and <B .
asked Oct 3, 2014 in CALCULUS by anonymous

1 Answer

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Best answer

A) The point (-5, 8) is located on the terminal arm of <A in standard position.

The above coordinate pair in second quadrant.

Angle A is in second quadrant.

From Pythagorean theorem,

r2 = x2 + y2

r = √[52 + 82]

r = √(25 + 64)

r = √89

 

B)

Find the angle of A:

sinA = opposite side/hypotenuse

sinA = 5/√89

= 5/9.43

A = sin -1 (0.5302)

A = 32.0205°

Sum of the angles in a triangle 180°

We now that <C = 90° and <A = 32.0205°

B = 180° - ( 90° + 32.0205°)

B = 57.9794°

<A = 32.0205° <B = 57.9794°.

 

answered Oct 4, 2014 by david Expert

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